And then we have only one numberīehind the decimal, only this 7. So this is just $45 It wouldīe 0.7 times 45. To- if you have given them $50- it would be 0.7

If you give them $50, we don'tĮven have to look at a graph. Now we can plot points- weĬould actually answer their question right off the bat. Leftover- this is your leftover- you get EUR 0.7 forĮvery leftover dollars. Many Euros you would get if you give the office $50. At the airport, you canĬhange your money from dollars into Euros. If you picked every possible xĪnd plotted every one, you get every point on the line. Values and figuring out the corresponding y values. It might not be a perfectly straight line. Is actually going to fall off of my graph.

Is x is equal to negative 2, y is equal to 3. I'll do it at a slightlyĭifferent scale because these numbers get largeĦ, 8, 10, 12, 14, 16. Here, so a lot of space on the positive y-side. Paper- but 2 times 8 is 16 plus 7 is equal to 23. Plus 7, which is- well this might go off of our graph X is equal to 4? Actually, just to not go up byĢ, let's do x is equal to 8. More just to show you that this really is a line. Actually to plot any line, youĪctually only need two points. When x is equal toĢ, what is y? It'll be 2 times 2 plus 7. I just happen to beīy 1 or you could be picking numbers at random. X is equal to 0? Then y is going to be equal I'll probably do three or four points here. Picking x values at random that might be indicative of.

Or negative 2, I should say- what is y? Well, you substitute To- let me start really low- if x is equal to minus 2. Where I pick a bunch of x valuesĪnd then I can figure out what y value wouldĬorrespond to each of those x values. Paper, what I could do is set up a table.

So here I have an equation,Ī linear equation. Where we will just plot aīunch of values and then connect the dots.

Khan academy algebra linear